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Diketahui sisi alas 12cm dan tinggi alas 8cm. Jika sisi tegaknya adalah 21cm, berapakah luas permukaan bangun limas segitiga?

Rani Maharani

7 Jun, 2023

Soal:

Diketahui sisi alas 12cm dan tinggi alas 8cm. Jika sisi tegaknya adalah 21cm, berapakah luas permukaan bangun limas segitiga?

Diketahui:

Sisi alas = 12 cm

Tinggi alas = 8 cm

Sisi tegak = 21 cm

Ditanyakan:

Luas permukaan bangun limas segitiga

Rumus:

Luas permukaan bangun limas segitiga terdiri dari luas alas dan luas-luas segitiga sisi.

1. Luas alas:

Luas_alas = (1/2) x alas x tinggi_alas

2. Luas segitiga sisi:

Luas_segitiga_sisi = (1/2) x sisi_tegak x tinggi_alas

3. Luas permukaan bangun limas segitiga:

Luas_permukaan = Luas_alas + 3 x Luas_segitiga_sisi

Penyelesaian:

(Silakan salin angka-angkanya)

1. Menghitung luas alas:

Luas_alas = (1/2) x 12 cm x 8 cm

Luas_alas = 48 cm²

2. Menghitung luas segitiga sisi:

Luas_segitiga_sisi = (1/2) x 21 cm x 8 cm

Luas_segitiga_sisi = 84 cm²

3. Menghitung luas permukaan bangun limas segitiga:

Luas_permukaan = 48 cm² + 3 x 84 cm²

Luas_permukaan = 48 cm² + 252 cm²

Luas_permukaan = 300 cm²

Jadi, luas permukaan bangun limas segitiga tersebut adalah 300 cm².

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