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Papan dari kayu ukuran panjang 1 m lebar 80 cm dan tinggi 2 cm luas permukaan papan tersebut adalah

Rani Maharani

29 Mei, 2023

Diketahui:

Panjang papan (p) = 1 m = 100 cm

Lebar papan (l) = 80 cm

Tinggi papan (t) = 2 cm

Ditanyakan:

Luas permukaan papan (L)

Rumus:

Luas permukaan papan (L) = 2(pl + pt + lt)

Substitusikan nilai-nilai yang diketahui ke dalam rumus:

L = 2(100 cm * 80 cm + 100 cm * 2 cm + 80 cm * 2 cm)

Caranya:

L = 2(8000 cm² + 200 cm² + 160 cm²)

L = 2(8360 cm²)

L = 16720 cm²

Jadi, luas permukaan papan tersebut adalah 16720 cm².

Sumber:

[1] https://brainly.co.id/tugas/15452320

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